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In a race, Jason's position was -11 1/5 feet relative to the leader after 1 3/4 minutes.

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In a race, Jason's position was -11 1/5 feet relative to the leader after 1 3/4 minutes.

In a race, Jason's position was -11 1/5 feet relative to the leader after 1 3/4 minutes. On average, how much did Jason's position relative to the leader change per minute? Enter your answer as a mixe
For the answer to the question above, the solution to the problem is as follows:The following asking for speed,Given:distance = -11 1/5 feettime =  1 3/4 minutesSolution:speed = distance/time = -11 1/5 feet / 1 3/4 minutes = (-54/5) / (7/4) = -216/35 = -6 6/35Therefore, Jason's position relative to the leader change per minute is -6 6/35 feet per minute.I hope my answer has come to your help. ...

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